Example Problem II-6-2 (Concluded)

Bay tide range is 0.96 m and is not symmetric about mean sea level, due to river flow.

Maximum channel velocities are determined from Figure II-6-27 (maximum ebb velocity)

)

Using Equation II-6-5, and substituting *U*Nmaxe for *V*Nm and *U*maxe for *V*m , and solving for *U*maxe

)

0.80 (2) (3.14) (0.65) (1.90) 107

' 2.08 m/s

'

666 (12.42) (3600)

From Figure II-6-28 (maximum flood velocity)

)

and in a manner similar to solving for ebb velocity, flood velocity is determined by

)

0.50 (2) (3.14) (0.65) (1.90) 107

' 1.30 m/s

'

666 (12.42) (3600)

Maximum discharges are determined from

River flow increases maximum ebb discharge and decreases maximum flood discharge, as one would expect.

The values are nearly balanced around the no-river-discharge value of 1,145 m3/s of Example 1.

Using Figure II-6-29, the value of ε (phase lag of bay tide relative to ocean tide) is determined to be 19 deg,

indicating high water occurs earlier than for the non-river-inflow condition of Example 1.

Hydrodynamics of Tidal Inlets

II-6-35

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